if var1 equals 1, and you run var2 = var1, that sets var2 to 1.

if list1 equals [1, 2, 3], and you run list2 = list1, that sets list2 to list1

so if you then run var1 = 2, var2 will still be 1

but if you run list1 = [3, 2, 1], list2 will give [3, 2, 1]

  • marcos@lemmy.world
    9·
    3 months ago

    Hum… No it won’t.

    It’s something you only really learn from C or Rust, but your operations will set both to the same list. If you go and change the list, you will change both, but if you set one to a different list, you won’t change the other list.

    In other words, if you do list1.push(4), you will change list2. But list1 = [3, 2, 1] won’t.